2+2sin^2=4cos^2x

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Solution for 2+2sin^2=4cos^2x equation:


Simplifying
2 + 2sin2 = 4cos2x

Solving
2 + 2in2s = 4cos2x

Solving for variable 'i'.

Move all terms containing i to the left, all other terms to the right.

Add '-2' to each side of the equation.
2 + -2 + 2in2s = -2 + 4cos2x

Combine like terms: 2 + -2 = 0
0 + 2in2s = -2 + 4cos2x
2in2s = -2 + 4cos2x

Divide each side by '2n2s'.
i = -1n-2s-1 + 2cn-2osx

Simplifying
i = -1n-2s-1 + 2cn-2osx

Reorder the terms:
i = 2cn-2osx + -1n-2s-1

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